A) 590V
B) 690V
C) 790V
D) 890V
Correct Answer: C
Solution :
After combination of drops \[{{(R)}^{3}}=2{{R}^{3}}\] \[R={{2}^{1/3}}R\] \[q=2q\] Thus, \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{R}\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2q}{{{2}^{1/3}}R}={{2}^{2/3}}V\] \[={{2}^{2/3}}(500)=790\,V\]You need to login to perform this action.
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