A) \[1.45\times {{10}^{-13}}N\]
B) zero
C) \[8.67\times {{10}^{-15}}N\]
D) \[3.87\times {{10}^{-15}}N\]
Correct Answer: A
Solution :
Electric field in between the capacitor plates is given by \[E=\frac{q}{{{\varepsilon }_{0}}A}\] or \[q={{\varepsilon }_{0}}A\times E\] \[=8.85\times {{10}^{-12}}\times 25\times {{10}^{-7}}\times 175\] \[=3.87\times {{10}^{-15}}C\] Magnetic force experienced by +ye plate is, \[{{F}_{m}}=qvB=1.45\times 10{{~}^{-13}}N\] in a direction out of plane of paper.You need to login to perform this action.
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