A) The body which has been thrown horizontally
B) The body which has been dropped
C) Both will reach the ground simultaneously
D) Depends on the velocity with which the first bod has been projected horizontally
Correct Answer: C
Solution :
Since, vertical displacement is same, as well as initial velocity in vertical downward direction is zero for both the bodies. So, \[h=\frac{gt_{1}^{2}}{2}\] (for horizontal throwing) \[h=\frac{gt_{2}^{2}}{2}\] (for dropping) \[\therefore \] \[{{t}_{1}}={{t}_{2}}\]You need to login to perform this action.
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