A) \[\frac{m}{h({{\rho }_{s}}+{{\rho }_{w}})}\]
B) \[\frac{m}{h{{\rho }_{w}}}\]
C) \[\frac{m}{h({{\rho }_{s}}-{{\rho }_{w}})}\]
D) \[\frac{m}{h({{\rho }_{w}}-{{\rho }_{s}})}\]
Correct Answer: D
Solution :
From equilibrium\[mg=Ah{{\rho }_{s}}\times g=Ah{{\rho }_{w}}\times g\]where A is required cross-section area \[\Rightarrow \]\[A=\frac{m}{h({{\rho }_{w}}-{{\rho }_{s}})}\]You need to login to perform this action.
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