A) \[\frac{17}{9}km/h\,and\,\frac{13}{9}km/h\]
B) \[\frac{13}{4}km/h\,and\,\frac{17}{4}km/h\]
C) \[\frac{17}{4}km/h\,and\,\frac{13}{4}km/h\]
D) \[\frac{13}{9}km/h\,and\,\frac{17}{9}km/h\]
Correct Answer: C
Solution :
Given, \[{{s}_{1}}=12,{{s}_{2}}=5,{{t}_{1}}=\frac{12}{4}=3h,{{t}_{2}}=\frac{5}{5}=1h\] \[\therefore \]Average speed \[=\frac{{{s}_{1}}+{{s}_{2}}}{{{t}_{1}}+{{t}_{2}}}=\frac{12+5}{3+1}\] \[=\frac{17}{4}km/h\] Average speed \[=\frac{displacement}{total\text{ }time}=\frac{AC}{4}=\frac{13}{4}km/h\]You need to login to perform this action.
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