A) 1
B) \[\sqrt{2}\]
C) 4
D) 2
Correct Answer: D
Solution :
At height R, the value of \[g=g{{\left( \frac{R}{R+R} \right)}^{2}}\] \[g=\frac{g}{4}\] \[T\propto \frac{1}{\sqrt{g}}\] \[\therefore \] \[\frac{{{T}_{2}}}{{{T}_{1}}}=\sqrt{\frac{g}{g/4}}=2\] \[{{T}_{2}}=2{{T}_{1}}\]You need to login to perform this action.
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