A) first order reaction with molecularity 1
B) second order reaction with molecularity 2
C) first order reaction with molecularity 2
D) second order reaction with molecularity 1
Correct Answer: B
Solution :
\[RCOOR+NaOH\xrightarrow[{}]{{}}RCOONa+ROH~\] \[Rate=k[RCOOR]\,[NaOH]\] Hence, order of reaction = 2 Molecularity = 2You need to login to perform this action.
You will be redirected in
3 sec