A) \[\frac{1}{4}m/s\]
B) \[\frac{1}{4}(\sqrt{3}-1)m/s\]
C) \[\frac{1}{8}m/s\]
D) \[\frac{1}{8}(\sqrt{6}-\sqrt{2})m/s\]
Correct Answer: D
Solution :
Using\[\frac{w}{\sin 30{}^\circ }=\frac{w}{\sin 105{}^\circ }\] \[\Rightarrow \] \[w=\frac{v\sin 30{}^\circ }{\sin 105{}^\circ }\] \[=\frac{v.\frac{1}{2}}{\frac{\sqrt{3}+1}{2\sqrt{2}}}=\frac{\sqrt{2}v}{\sqrt{3}+1}\] \[=\frac{\sqrt{2}v(\sqrt{3}-1)}{3-1}=\frac{v}{\sqrt{2}}(\sqrt{3}-1)\] \[=\frac{1}{4\sqrt{2}}(\sqrt{3}-1)=\frac{1}{8}(\sqrt{6}-\sqrt{2})m/s\]You need to login to perform this action.
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