A) One
B) Two
C) Three
D) Four
Correct Answer: C
Solution :
Centres and radii of circles are\[{{C}_{1}}(0,0),{{r}_{1}}=1\] and\[{{C}_{2}}(2,0),{{r}_{2}}=\sqrt{4-3}=1\] Now, \[{{C}_{1}}{{C}_{2}}=\sqrt{{{(2-0)}^{2}}+0}=2={{a}_{1}}+{{a}_{2}}\] Hence, two circles touch each other externally, so there are 3 common tangents are possible.You need to login to perform this action.
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