A) \[3\times {{10}^{12}}N{{m}^{-2}}\]
B) \[2\times {{10}^{12}}N{{m}^{-2}}\]
C) \[{{10}^{12}}N{{m}^{-2}}\]
D) None of these
Correct Answer: A
Solution :
\[Y=2\eta (1+\sigma )\]For no transverse strain \[(\sigma =0)\]\[Y=2\eta \Rightarrow n=\frac{Y}{2}=3\times {{10}^{12}}N/{{m}^{2}}\]You need to login to perform this action.
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