A) 7
B) 9
C) 10
D) 6
Correct Answer: B
Solution :
\[1\text{ }N\text{ }HCl\]solution means; 36.5 g of\[HCl\]are dissolved in 1000 mL. (\[\because \] Equivalent wt. of\[HCl=36.5\]) \[\therefore \]100 mL of\[HCl\]solution contains\[HCl\] Similarly 100 mL of\[HCl\]solution contains Now, \[\frac{Eq.\text{ }wt.\text{ }of\text{ }metal}{Weight\text{ }of\text{ }metal\text{ }in\text{ }solution}\] \[=\frac{Eq.\text{ }wt.\text{ }of\text{ }acid}{Weight\text{ }of\text{ }acid\text{ }in\text{ }solution}\] \[\frac{E}{0.9}=\frac{36.5}{3.65}\] \[E=9\]You need to login to perform this action.
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