A) \[-1,-2\]
B) \[-1,2\]
C) \[1,-2\]
D) \[1,2\]
Correct Answer: B
Solution :
Since,\[\Delta SPM\]is an equilateral triangle. Therefore, \[SP=PM=SM\] \[\therefore \] \[\angle PMZ=90{}^\circ \] and \[\angle PMS=60{}^\circ \] \[\therefore \] \[\angle SMZ=30{}^\circ \] Now, in right angle\[\Delta SMZ\] \[\sin 30{}^\circ =\frac{SZ}{SM}\] \[\Rightarrow \] \[\frac{1}{2}=\frac{2a}{SM}\] \[\Rightarrow \] \[SM=4a\] \[\Rightarrow \] \[PM=4a\] \[(\because PM=SM)\]You need to login to perform this action.
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