A tank is filled with water upto height H. When a hole is made at a distance h below the level of water. What will be the horizontal range of water jet?
A) \[2\sqrt{h(H-h)}\]
B) \[4\sqrt{h(H+h)}\]
C) \[4\sqrt{h(H-h)}\]
D) \[2\sqrt{h(H+h)}\]
Correct Answer:
A
Solution :
Applying Bernoullis theorem, The velocity of water at point \[v=\sqrt{2gh}\] Time taken to reach point C is t So, \[H-h=\frac{1}{2}g{{t}^{2}}\] \[t=\sqrt{\frac{2(H-h)}{g}}\] ?.(i) Now, horizontal range \[R=vt\] \[=\sqrt{2gh}\times \sqrt{\frac{2(H-h)}{g}}=2\sqrt{(H-h)}h\]