A) \[2:(n-3)\]
B) \[(n-1):2\]
C) \[(n-2):2\]
D) \[(n-3):2\]
Correct Answer: D
Solution :
Let d be the common difference of AP. Since, \[{{a}_{7}}=15\] \[\therefore \] \[{{a}_{2}}=15-5d\] and \[{{a}_{12}}=15+5d\] Now, \[{{a}_{2}}{{a}_{7}}{{a}_{12}}=(15-5d)(15)(15+5d)\] \[=15.25(3-d)(3+d)\] \[=375(9-{{d}^{2}})\] Clearly, this will be greatest, if\[d=0\]You need to login to perform this action.
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