A) \[C{{H}_{3}}COC{{H}_{3}}\]
B) \[{{C}_{6}}{{H}_{5}}CHO\]
C) \[{{C}_{6}}{{H}_{5}}COC{{H}_{2}}C{{H}_{3}}\]
D) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}CHO\]
Correct Answer: B
Solution :
\[\underset{Propanoic\text{ }acid}{\mathop{C{{H}_{3}}C{{H}_{2}}COOH}}\,\xrightarrow[-S{{O}_{2}}.-HCl]{SOC{{l}_{2}}}\underset{Propanoyl\text{ }chloride\text{ }(A)}{\mathop{C{{H}_{3}}C{{H}_{2}}COCl}}\,\] \[\xrightarrow[-N{{H}_{4}}Cl]{N{{H}_{3}}(excess)}\underset{Propionamide\,(B)}{\mathop{C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}}}\,\xrightarrow[{}]{B{{r}_{2}}/KOH}\] \[\underset{ethylamine\text{ }(C)}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\]You need to login to perform this action.
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