A) zero
B) one
C) four
D) eight
Correct Answer: C
Solution :
Given,\[{{y}_{1}}=\pi sin\text{ }200\text{ }\pi t\] This equation comparing with \[y=a\sin 2\pi {{x}_{1}}t\] Then, \[{{n}_{1}}=100\] and \[{{y}_{1}}=a\sin 208\pi t\] This equation comparing with \[y=a\sin 2\pi {{n}_{2}}t\] \[{{n}_{2}}=104\] Hence, the number of beats \[={{n}_{2}}-{{n}_{1}}\] \[=104-100=4\]You need to login to perform this action.
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