A) 80V
B) \[8\times {{10}^{6}}V\]
C) 9V
D) \[9\times {{10}^{5}}V\]
Correct Answer: B
Solution :
\[V=\frac{I}{4\pi {{\varepsilon }_{0}}}.\frac{q}{R}\] \[\because \] \[(q=z)\] \[=9\times {{10}^{9}}\times \frac{50\times 1.6\times {{10}^{-19}}}{9\times {{10}^{-15}}}\] \[=8\times {{10}^{6}}V\]You need to login to perform this action.
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