A) 80 kg wt
B) 240 kg wt
C) 200 kg wt
D) 160 kg wt
Correct Answer: D
Solution :
Breaking force = Breaking stress\[\times \]area of cross-section of wire Breaking force\[\propto {{r}^{2}}\](breaking distance is constant) \[\frac{{{F}_{2}}}{{{F}_{1}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}\] \[{{F}_{2}}=\frac{4\times 40}{1}=160\,kg\,wt\]You need to login to perform this action.
You will be redirected in
3 sec