A) \[80{}^\circ C\]
B) \[444{}^\circ C\]
C) \[333{}^\circ C\]
D) \[171{}^\circ C\]
Correct Answer: D
Solution :
For open mouth vessel, pressure is constant volume is also given constant \[PV=\mu RT\] \[=\left( \frac{m}{M} \right)RT\] \[T\propto \frac{1}{M}=\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{{{M}_{2}}}{{{M}_{1}}}\] \[\frac{1}{4}\]th part escape so remaining mass in the vessel \[{{M}_{2}}=\frac{1}{4}{{M}_{1}}\] \[\frac{(273+60)T}{{}}=\frac{3/4{{M}_{1}}}{{{M}_{1}}}\] \[T=444K=171{}^\circ C\]You need to login to perform this action.
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