A) 200 J
B) 100J
C) zero
D) 1000J
Correct Answer: A
Solution :
Net work done in sliding a body upto a height h on inclined plane = work done against gravitational force\[+\]work done against frictional force \[W~={{W}_{g}}~+~{{W}_{f}}\] \[W=300\,J\] but \[{{W}_{g}}=mgh\] \[=2\times 10\times 10=200J\] Putting in Eq. (i), we get \[300=200+{{W}_{f}}\] \[{{W}_{f}}=300-200=100\,J\]You need to login to perform this action.
You will be redirected in
3 sec