A) \[\frac{{{E}^{2}}}{r}\]
B) \[\frac{{{E}^{2}}}{2r}\]
C) \[\frac{{{E}^{2}}}{3r}\]
D) \[\frac{{{E}^{2}}}{4r}\]
Correct Answer: D
Solution :
\[i=\frac{E}{R+r}\] \[P={{i}^{2}}R\] \[P=\frac{{{E}^{2}}R}{{{(r+R)}^{2}}}\] Power will be maximum when \[r=R\] \[{{p}_{\max }}=\frac{{{E}^{2}}}{4r}\]You need to login to perform this action.
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