A) \[{{q}_{3}}+3{{q}_{2}}-2{{q}_{1}}\]
B) \[2{{q}_{1}}-{{q}_{3}}-2{{q}_{2}}\]
C) \[{{q}_{3}}+3{{q}_{2}}-6{{q}_{1}}\]
D) \[{{q}_{1}}+{{q}_{2}}-{{q}_{3}}\]
Correct Answer: C
Solution :
\[\Delta H=(BE)\]of all bonds in reactants - (BE) of all bonds in products \[={{q}_{3}}+3{{q}_{2}}-6{{q}_{1}}\] (each\[N{{H}_{3}}\]has three\[N-H\] bonds)You need to login to perform this action.
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