A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
The parametric form of the given equation is \[x=t\]and\[y={{t}^{2}}\]. The equation of any tangent at t is\[2xt=y+{{t}^{2}}\] On differentiating, we get\[2t={{y}_{1}}\] On putting this value in the equation of tangent, we have \[\frac{2x{{y}_{1}}}{2}=y+{{\left( \frac{{{y}_{1}}}{2} \right)}^{2}}\] \[\Rightarrow \] \[4x{{y}_{1}}=4y+y_{1}^{2}\] So, the order of this equation is one.You need to login to perform this action.
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