A) \[x=y\]
B) \[2x=y\]
C) \[x=2y\]
D) \[x+y=0\]
Correct Answer: A
Solution :
Let\[(h,k)\]be the mid-point of the chord \[7x+y-1=0\] Then, \[\frac{hx}{1}+\frac{ky}{7}=\frac{{{h}^{2}}}{1}+\frac{{{k}^{2}}}{7}\] ...(i) and \[7x+y=1\] ...(ii) represent the same straight line. \[\Rightarrow \] \[\frac{h}{7}=\frac{k}{7}\] \[\Rightarrow \] \[h=k\] So, the equation of the line joining (0, 0) and (h, k) is \[y-k=0\].You need to login to perform this action.
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