A) 0.01 mm
B) 0.075 mm
C) 0.1 mm
D) 0.15mm
Correct Answer: C
Solution :
Increase in length \[l=\frac{mgL}{AY}\] \[=\frac{1\times 10\times 1.1}{1.1\times {{10}^{11}}\times {{10}^{-6}}}m=0.1\,mm\]?(i)You need to login to perform this action.
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