A) 0.15 M urea and 0.05 M \[1.22f\]
B) 0.15M urea and 0.1 M\[f\]
C) 0.15 M urea and 0.15 M glucose
D) 0.1\[1.27f\] and 0.05 M \[\text{1}.0\text{1}\times \text{1}{{0}^{\text{5}}}\text{ N}/{{\text{m}}^{\text{2}}}\]
Correct Answer: C
Solution :
0.15 M urea and 0.15 M glucose solution are isotonic because both on dissociation give only one molecule, while \[{{\sin }^{-1}}\left( \frac{8}{9} \right)\] give two molecules and \[\beta =0.\text{1}\] will give three molecules.
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