A) -9
B) -81
C) -27
D) 81
Correct Answer: B
Solution :
Given,\[\frac{2\omega }{3}\] and \[\mu =\frac{3}{2}\] \[\mu =\frac{4}{3}\] \[{{\sin }^{-1}}\left( \frac{9}{8} \right)\] \[{{45}^{o}}\] Now, \[{{60}^{o}}\] (\[{{\sin }^{-1}}\left( \frac{8}{9} \right)\]AB is of order 3) \[\beta =0.\text{1}\]You need to login to perform this action.
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