question_answer

Light is refracted \[{{\sin }^{-1}}\left( \frac{9}{8} \right)\]to water \[{{45}^{o}}\] for total internal reflection sin i will be equal to    

A)   \[{{60}^{o}}\]                    

B) \[{{\sin }^{-1}}\left( \frac{8}{9} \right)\]

C) \[\beta =0.\text{1}\]                                     

D) \[{{P}_{1}}\]

Correct Answer: D

Solution :

                We know that for total internal reflection, the incident angle must be greater than or equal to the critical angle for which the reflected angle is 90°. Here,        \[{{(Kg)}^{1/2}}\] \[{{(Kg)}^{-1/2}}\] \[{{(Kg)}^{2}}\]