A) \[[{{m}^{0}}{{L}^{-1}}{{T}^{-2}}]\]
B) \[[{{m}^{0}}{{L}^{0}}{{T}^{0}}]\]
C) \[1.5\mu \]
D) \[\mu \]
Correct Answer: B
Solution :
\[y=A\sin (Bx+Ct+D)\] As each term inside the bracket is dimension less, so \[NaCl\] \[O{{H}^{-}}\] \[{{H}_{2}}O\] C and D is dimensionless \[\text{C}{{\text{u}}_{\text{2}}}\] \[{{\left( \text{SCN} \right)}_{\text{2}}}.\] \[{{K}_{6}}=\frac{RT_{0}^{2}}{1000\Delta {{H}_{v}}}\]
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