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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2014

  • question_answer
    The equation of stationary wave along a stretched string is given by \[{{(Kg)}^{1/2}}\], where x and y are in cm and \[{{(Kg)}^{-1/2}}\]in second. The separation between two adjacent nodes is

    A) 1.5 cm                                  

    B) 3 cm   

    C) 6 cm                      

    D) 4 cm

    Correct Answer: B

    Solution :

                    The equation of stationary wave is \[1.11f\]                 ...(i) where, a is amplitude, \[1.22f\] is wavelength and T is periodic time. \[f\]                       ??.(ii) Comparing Eqs. (i) and (ii), we get \[1.27f\] \[\text{1}.0\text{1}\times \text{1}{{0}^{\text{5}}}\text{ N}/{{\text{m}}^{\text{2}}}\] Distance between adjacent nodes is \[\text{9}.\text{13}\times \text{1}{{0}^{\text{4}}}\text{ N}/{{\text{m}}^{\text{2}}}\]


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