JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2014

  • question_answer
    A point P lies on the axis of a ring of mass M and radius R at a distance 2R from its centre O. A small particle starts from R and reaches Q  under gravitational attraction only. Its speed of O will be

    A) zero                      

    B) \[CaC{{l}_{2}}\]

    C)  \[CaC{{l}_{2}}\]               

    D) \[\text{MgS}{{\text{O}}_{\text{4}}}\]

    Correct Answer: D

    Solution :

                    avitation potential at a point P distance r from center of ring lying on the axis is \[4.5\Omega \] \[5\Omega \] \[\frac{\sqrt{3}}{1}\] Gravitational potential at centre O of the ring is \[\frac{(\sqrt{3}+1)}{(\sqrt{3}-1)}\] Kinetic energy \[\frac{(\sqrt{3}+1)}{1}\] \[\frac{4}{3}\] \[4\mu F\] \[10\mu F\]


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