A) 5.65 h
B) 4.65h
C) 3.65 h
D) 6.65 h
Correct Answer: B
Solution :
\[\text{3}.\text{18}\times \text{1}{{0}^{8}}m/s\] \[\text{3}.\text{33}\times {{10}^{\text{8}}}\text{ m}/\text{s}\] Initially there are \[\theta =\text{45}{}^\circ \] atoms which reduces to \[\frac{1}{3}M{{L}^{2}}\] atoms after time t min \[=\frac{2.303}{10}\log \frac{100}{80}=0.223{{\min }^{-1}}\] \[\frac{3}{4}M{{L}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec