A) zero
B) \[CaC{{l}_{2}}\]
C) \[CaC{{l}_{2}}\]
D) \[\text{MgS}{{\text{O}}_{\text{4}}}\]
Correct Answer: D
Solution :
avitation potential at a point P distance r from center of ring lying on the axis is \[4.5\Omega \] \[5\Omega \] \[\frac{\sqrt{3}}{1}\] Gravitational potential at centre O of the ring is \[\frac{(\sqrt{3}+1)}{(\sqrt{3}-1)}\] Kinetic energy \[\frac{(\sqrt{3}+1)}{1}\] \[\frac{4}{3}\] \[4\mu F\] \[10\mu F\]You need to login to perform this action.
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