A) \[{{m}_{PB}}\]
B) \[m_{PA}^{2}+m_{_{PB}}^{2}=4\]
C) \[{{y}^{2}}=2x(x-a)\]
D) \[{{y}^{2}}=x(x-a)\]
Correct Answer: B
Solution :
Order of equivalent conductance is \[\text{4}\times \text{1}{{0}^{\text{5}}}\].smaller cations are hardly hydrated in aqueous solution gives the larger hydrated radius and smaller ionic Speed and equivalent conductance.
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