A) 16
B) 4
C) \[0.5\Omega \]
D) \[1\Omega \]
Correct Answer: C
Solution :
According to Kepler's third law, \[\text{T}-\text{mg}=\frac{m{{V}^{2}}}{l}\] \[\text{3mg}-\text{mg }=\frac{m{{V}^{2}}}{l}\] \[V=\sqrt{2gl}\] \[\theta \]You need to login to perform this action.
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