A) \[\text{2}\times \text{1}{{0}^{\text{37}}}\]
B) \[\text{2}\times \text{1}{{0}^{\text{39}}}\]
C) \[LiCl,NaCl,KCl\]
D) \[\text{LiCl}>\text{NaCl}>\text{KCl}\]
Correct Answer: C
Solution :
\[\text{BeO}\] \[HCl\] \[BeC{{l}_{2}}\] \[BeC{{l}_{2}}\]You need to login to perform this action.
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