A) \[{{\left( \text{C}{{\text{H}}_{\text{3}}} \right)}_{\text{2}}}\text{CHOH}\]
B) \[\int_{1}^{4}{{{\log }_{e}}[x]dx}\]
C) \[\text{lo}{{\text{g}}_{\text{e}}}\text{6}\]
D) \[\text{lo}{{\text{g}}_{\text{e}}}3\]
Correct Answer: C
Solution :
\[\text{phenyl alanine }\left( {{\text{C}}_{6}}{{\text{H}}_{5}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ N{{H}_{2}} \end{smallmatrix}}{\mathop{\text{CH}}}\,\text{COOH} \right)\text{ }\] \[{{R}_{2}}Si{{(OH)}_{2}}\] Thus, \[R-N{{H}_{2}}+{{H}_{2}}OR\overset{\oplus }{\mathop{N}}\,{{H}_{3}}+O{{H}^{-}}\] \[k=\frac{[R-\overset{\oplus }{\mathop{N}}\,{{H}_{3}}][O{{H}^{-}}]}{[RN{{H}_{2}}][{{H}_{2}}O]}\] \[k[{{H}_{2}}O]=\frac{[R-\overset{\oplus }{\mathop{N}}\,{{H}_{3}}][O{{H}^{-}}]}{[R-N{{H}_{2}}]}\] \[{{k}_{b}}=\frac{[R-\overset{+}{\mathop{N}}\,{{H}_{3}}][O{{H}^{-}}]}{[R-N{{H}_{2}}]}\] \[p{{k}_{b}}=-\log {{k}_{b}}\]You need to login to perform this action.
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