A) fog is always periodic
B) gof is never periodic
C) gof is always periodic
D) None of the above
Correct Answer: C
Solution :
Let T be the period of \[f(x)\]. Then, \[f(x+T)=f(x)for\,all\,x\] \[\Rightarrow \] \[gof(x+T)=g[f(x+T)]\] \[\Rightarrow \] \[gof(x+T)=g(x)\] Hence, gof is a periodic with period T.You need to login to perform this action.
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