question_answer

The coordinates of the foot of the perpendicular drawn from the point (3, 4) on the line \[k=\frac{2}{3},l=\frac{2}{3}\], is

A) \[k=-\frac{1}{3},l=-\frac{1}{6}\]                

B) \[(1,5)\]              

C) \[(-5,1)\]                             

D) \[(1,-5)\]

Correct Answer: A

Solution :

Let the given point be \[\text{BeO}\] and line be \[\text{Ba}{{\text{O}}_{\text{2}}}\] \[\text{MgO}\]                 \[\text{CaO}\] Let h, k be the coordinates of the foot of the perpendicular. Then \[C{{H}_{3}}\,\,\overset{+}{\mathop{{{H}_{2}}}}\,\] \[\text{C}{{\text{H}}_{\text{2}}}=\text{CH}\]     \[\text{CH}=\overset{+}{\mathop{\text{C}}}\,\]and                 \[\overset{+}{\mathop{{{\text{C}}_{6}}{{H}_{5}}}}\,\] \[{{\text{C}}_{6}}{{H}_{5}}C{{H}_{2}}\overset{\bullet \bullet }{\mathop{C{{H}_{2}}}}\,\]                \[{{\text{C}}_{6}}{{H}_{5}}\overset{\bullet \bullet }{\mathop{C{{H}_{2}}}}\,\]and \[{{(C{{H}_{3}})}_{2}}SiC{{l}_{2}}\] \[{{(C{{H}_{3}})}_{4}}Si\]              \[{{(C{{H}_{3}})}_{3}}SiCl\]and \[C{{H}_{3}}SiC{{l}_{3}}\] Hence, the coordinates of the foot of perpendicular are \[RN{{H}_{2}}+{{H}_{2}}OR-\overset{+}{\mathop{N{{H}_{3}}}}\,+O{{H}^{-}}\]