A) \[f(x)=|x|\]
B) \[f(x)=2{{x}^{3}}+3\]
C) \[\frac{2\pi }{3}\]
D) \[\frac{\pi }{3}\]
Correct Answer: C
Solution :
Point circles of the coaxial system are \[\text{2}\times \text{1}{{0}^{\text{34}}}\] and \[\text{2}\times \text{1}{{0}^{\text{37}}}\] \[\text{2}\times \text{1}{{0}^{\text{39}}}\] \[LiCl,NaCl,KCl\] and \[\text{LiCl}>\text{NaCl}>\text{KCl}\] \[\text{KCl}>\text{NaCl}>\text{LiCl}\]Equation of coaxial system is \[\text{NaCl}>\text{KCl}>\text{LiCl}\] \[\text{LiCl}>\text{KCl}>\text{NaCl}\] ?(i) It passes through (0, 0). Then, \[{{C}_{2}}{{H}_{5}}OH\] \[C{{H}_{3}}OH\] Then, from Eq. (i), \[\text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{COOH}\] \[{{\left( \text{C}{{\text{H}}_{\text{3}}} \right)}_{\text{2}}}\text{CHOH}\] \[\int_{1}^{4}{{{\log }_{e}}[x]dx}\]\[\text{lo}{{\text{g}}_{\text{e}}}\text{6}\] \[\text{lo}{{\text{g}}_{\text{e}}}3\] \[\text{lo}{{\text{g}}_{\text{e}}}2\]\[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\] \[5{{h}^{2}}=ab\]\[5{{h}^{2}}=9ab\]
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