A) 2:1
B) 3:2
C) 4:-1
D) 1 :1
Correct Answer: C
Solution :
For first ball, \[\Delta n=6-\frac{15}{2}=-\frac{3}{2}\] \[\because \] For second ball \[\Delta H=\Delta U+RT.\Delta n\] \[\therefore \] \[-3268=\Delta U+8.314\times {{10}^{-13}}\times 293\times \left( \frac{-3}{2} \right)\] \[\therefore \] \[\Delta U=-3268+\frac{3}{2}\times 8.314\times {{10}^{-13}}\times 298\] \[=-3268++3.716=-3264\,KJ\,mo{{l}^{-1}}\]You need to login to perform this action.
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