A) \[\Delta x=\lambda /3\]
B) \[\sin \theta =\frac{\Delta x}{d}\]
C) \[\Rightarrow \]
D) \[\sin \theta =\frac{\lambda }{3d}\]
Correct Answer: A
Solution :
Given, two equal forces P and their resultant is also P. \[\therefore \] \[P=\sqrt{{{p}^{2}}+{{p}^{2}}+2{{p}^{2}}\cos \theta }\] \[\Rightarrow \] \[p=\sqrt{2}p\sqrt{1+\cos \theta }\] \[\Rightarrow \] \[\frac{1}{\sqrt{2}}=\sqrt{1+\cos \theta }\] \[\Rightarrow \] \[\frac{1}{2}=1+\cos \theta \] \[\Rightarrow \] \[\cos \theta =\frac{-1}{2}\Rightarrow \theta =\frac{2\pi }{3}\]
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