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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2015

  • question_answer
    A bag contains 3 black, 3 white and 2 red balls. Three balls are drawn without replacement one-by-one. The probability that the third ball is red, is

    A) \[\theta ={{\sin }^{-1}}\left[ \frac{\lambda }{3d} \right]\]                             

    B) \[V=\frac{Q}{C}=Q.\frac{d}{{{\varepsilon }_{0}}A}\]       

    C) \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{500}{800}\]                               

    D) \[=\frac{3}{8}=0.375\]

    Correct Answer: D

    Solution :

    Three possible cases arise
    \[IIst\] draw \[IInd\] draw \[III\text{ }rd\]draw
    Red Non-red Non-red Non-red Red Non-red Red Red Red
    \[\therefore \]  Required probability \[=\frac{2}{8}\times \frac{6}{7}\times \frac{1}{6}+\frac{6}{8}\times \frac{2}{7}\times \frac{1}{6}+\frac{6}{8}\times \frac{5}{7}\times \frac{2}{6}\] \[=\frac{2}{56}+\frac{2}{56}+\frac{10}{56}=\frac{14}{56}\]


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