A) \[=160\times {{10}^{5}}W\] is discontinuous at \[=160MW\]
B) \[=\text{36}0\,\text{rpm}\]is continuous at \[=\frac{\text{36}0}{60}\,\text{rps}\]
C) \[=\text{ 6}0\text{ rps}\] is continuous at \[=\text{ 6}\times \text{number of holes}\]
D) None of the above
Correct Answer: A
Solution :
\[\underset{x\to {{0}^{-}}}{\mathop{\lim }}\,f(x)=\underset{h\to 0}{\mathop{\lim }}\,2(0-h)=0\] And \[\underset{x\to {{0}^{+}}}{\mathop{\lim }}\,f(x)=\underset{h\to 0}{\mathop{\lim }}\,2(0+h)+1=1\] \[\because \] \[\underset{x\to {{0}^{-}}}{\mathop{\lim }}\,f(x)\ne \underset{x\to {{0}^{+}}}{\mathop{\lim }}\,f(x)\] \[\therefore \] \[f(x)\]is discontinuous at \[x=0\].
You need to login to perform this action.
You will be redirected in
3 sec
