A) \[\left( \text{Z}=\text{23} \right)\]
B) \[HCl\]
C) \[\text{BeO}\]
D) \[\text{Ba}{{\text{O}}_{\text{2}}}\]
Correct Answer: D
Solution :
\[C{{F}_{2}}C{{l}_{2}}\xrightarrow{hv}\overset{\bullet }{\mathop{Cl}}\,+C{{F}_{2}}\overset{\bullet }{\mathop{Cl}}\,\] \[\overset{\bullet }{\mathop{Cl}}\,+{{O}_{3}}\xrightarrow{{}}Cl\overset{\bullet }{\mathop{O}}\,+{{O}_{2}}\] At equalibrium \[Cl\overset{\bullet }{\mathop{O}}\,+O\xrightarrow{{}}\overset{\bullet }{\mathop{Cl}}\,+{{O}_{2}}\] Now.\[\Delta n=1-2=-1\]You need to login to perform this action.
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