A) (a) \[=\frac{M}{k}(L-x)g\]
B) \[{{T}_{x}}=\frac{Mg(L-x)}{L}\]
C) \[\left( \frac{N}{{{N}_{0}}} \right)={{\left( \frac{1}{2} \right)}^{n}}\]
D) \[\frac{1}{16}={{\left( \frac{1}{2} \right)}^{n}}\]
Correct Answer: A
Solution :
Let \[y=x+c\] be a tangent to\[\frac{{{x}^{2}}}{3}-\frac{{{y}^{2}}}{2}=1\]. Then. \[{{c}^{2}}=3-2\] \[\Rightarrow \] \[{{c}^{2}}=1\] \[\Rightarrow \] \[c=\pm 1\] So, the required tangents are \[y=x\pm 1\]
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