JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2015

  • question_answer
    The Young's modulus of the material of a wire is\[{{t}^{-1}}\]. If the elongation strain is 2%, then the energy stored in the wire per unit volume is \[{{t}^{\frac{-1}{2}}}\]is

    A) \[{{t}^{\frac{1}{2}}}\]

    B) \[t\]

    C) \[[FL{{T}^{-2}}]\]

    D) \[[F{{L}^{2}}{{L}^{-2}}]\]

    Correct Answer: A

    Solution :

    Per unit volume energy stored \[{{P}_{1}}+{{P}_{2}}=0\,\,or\,\,{{P}_{1}}=-{{P}_{2}}\,\,or\,|{{P}_{1}}|=|{{P}_{2}}|\] \[\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{|{{P}_{1}}|}{|{{P}_{2}}|}=1\] \[10\Omega \] \[\text{ABD}=\text{5}+\text{1}0=\text{15}\Omega \] \[\text{ACD}=\text{1}0+\text{2}0=\text{3}0\Omega \] \[R=\frac{15\times 30}{15\times 30}=10\Omega \]                 \[I=\frac{5V}{10\Omega }=0.5A\]                 \[p\propto T\]


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