A) 500MW
B) 20MW
C) 160MW
D) 80MW
Correct Answer: C
Solution :
Work \[V\propto \frac{1}{r}\] \[\text{mL}+\text{mc}\left( \text{1}00-\text{8}0 \right)=\left( \text{1}.\text{1}+0.0\text{2} \right)\text{c}\left( \text{8}0-\text{15} \right)\] power\[m[540+1\times 20]=1.12\times 1\times 65\] \[m=\frac{1.12\times 65}{560}=0.13kg\] \[t=\frac{A}{{{A}_{0}}}\sqrt{\frac{2H}{g}},\,\,\,i.e,\,\,\,t\propto \sqrt{H}\]You need to login to perform this action.
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