A) \[5V\]
B) \[{{l}_{AC}}=\sqrt{2}{{l}_{EF}}\]
C) \[{{l}_{AC}}={{l}_{EF}}\]
D) \[\sqrt{2}{{l}_{AC}}={{l}_{EF}}\]
Correct Answer: D
Solution :
Torque about the point (-1, -1) \[\frac{4{{x}^{3}}}{4}-\frac{2x}{2}=0\] \[\Rightarrow \] \[x=0,x=\pm 1\] \[{{U}_{\min }}(x=\pm 1)=\frac{1}{4}-\frac{1}{2}=\frac{-1}{4}\text{J}\]You need to login to perform this action.
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