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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2015

  • question_answer
    A\[10\mu F\]capacitor is charged to 500 V and then its plates are joined together through a resistance of \[100\Omega \]. The heat produced

    A)  250J                                     

    B) \[\text{25}.0\text{ at}{{\text{m}}^{\text{3}}}\]

    C) 500J                                      

    D) \[\text{1}.\text{33 at}{{\text{m}}^{\text{3}}}\]

    Correct Answer: D

    Solution :

    Heat produced = Energy stored in capacitor \[{{I}_{AD}}={{I}_{EF}}+\frac{m{{d}^{2}}}{4}\] \[=\frac{m{{d}^{2}}}{12}+\frac{m{{d}^{2}}}{4}\left[ as\,{{I}_{EF}}=\frac{m{{d}^{2}}}{12} \right]\]


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